SOLUTION: Solve: a: (2x + 3)^2 = 5 b: 2(x - 5)^2 = 3 (mark answers a and b)

Algebra.Com
Question 184470: Solve:
a: (2x + 3)^2 = 5
b: 2(x - 5)^2 = 3
(mark answers a and b)

Answer by kailuen(7)   (Show Source): You can put this solution on YOUR website!
(2x + 3)^2 = 5
4x^2+12x+9-5=0
4x^2+12x+4=0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=80 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: -0.381966011250105, -2.61803398874989. Here's your graph:

x=-2.6, x= -0.38

2(x - 5)^2 = 3
2(x^2-10x+25)=3
2x^2-20x+47=0
x=3.775
x=6.224

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