SOLUTION: 9. Find the volume of each cylinder with the given dimensions. Round your answer to the nearest hundredth. a) R=8.1 cm H= 4 cm b) R= 9m H= 23.5m

Algebra.Com
Question 182902: 9. Find the volume of each cylinder with the given dimensions. Round your answer to the nearest hundredth.
a) R=8.1 cm H= 4 cm
b) R= 9m H= 23.5m

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!

The volume of a cylinder is given by:



Just put in the numbers for r and h and then do the arithmetic.

By the way, rounding your answers to the nearest hundredth is utterly inappropriate in both of these problems. The results of calculations based on measurements should never be expressed to a precision greater than the least precise given measurement. Problem a) should be expressed to the nearest centimeter, and problem b) to the nearest meter. And using 3.14 for is plenty close enough here. That's not to say you shouldn't follow instructions, it's just that IMHO, the instructions are wrong.

John



RELATED QUESTIONS

9. Find the volume of each cylinder with the given dimensions. Round your answer to (answered by checkley77)
The volume V of a cylinder varies jointly with the height h and the radius squared r^2,... (answered by Alan3354)
Find the surface area and volume of a cylinder with the given dimensions. Round to the... (answered by zerosignal)
Find the volume of a sphere with a diameter of 25 cm. Approximate square root as 3.14 and (answered by stanbon)
The diameter of the base of a cylinder is 26 cm. The height of the cylinder is 15 cm.... (answered by Cromlix)
The diameter of the base of a cylinder is 22 cm. The height of the cylinder is 16 cm.... (answered by lwsshak3)
I need a little help with this one. The volume of a cylinder (think about the volume of... (answered by stanbon)
For a cylinder with a surface area of 10 , what is the maximum volume that it can have?... (answered by math_tutor2020)
The volume of a cylinder (think about the volume of a can) is given by V = πr2h... (answered by ankor@dixie-net.com)