SOLUTION: a rectangular garden is 9 feet longer than it is wide. A second rectangular garde is planned so that it will be 6 feet wider and twice as long as the first. Find the area of the fi
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Question 182787: a rectangular garden is 9 feet longer than it is wide. A second rectangular garde is planned so that it will be 6 feet wider and twice as long as the first. Find the area of the first garden if the sum of the areas of both gardens will be 528 square feet.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Area of first garden of width x and length x + 9:
 = x^2 + 9x )
Area of second garden of width x + 6 and length 2(x + 9):
(2x + 18) = 2x^2 + 15x + 108)
The two areas sum to 528:
 + (2x^2 + 15x + 108) = 528)
Simplify:
Solve for x and then use the expression above for the area of the first garden to calculate your answer. Hint: The quadratic factors, but one of the roots will be extraneous.
John
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