SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function f(x) = -2x^2+2x+1

SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function f(x) = -2x^2+2x+1

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Question 182769: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function f(x) = -2x^2+2x+1
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
f(x) = -2x^2+2x+1
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vertex is at (1/2,3/2)
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line if symmetry is at x=1/2
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maximum is at y=3/2
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