SOLUTION: Okay this is my last question.
on this itsays...
14-2i Over 3+i.
I dont know if that makes sense to you
But i think i learned something about taking the conjucate of 3+i w
Algebra.Com
Question 181601: Okay this is my last question.
on this itsays...
14-2i Over 3+i.
I dont know if that makes sense to you
But i think i learned something about taking the conjucate of 3+i which is 3-1, but i dont know where to go from there, or if im even doing it right.
Found 2 solutions by stanbon, ankor@dixie-net.com:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
14-2i Over 3+i.
-------------
= [(14-2i)(3-i)] / [(3+i)(3-i)]
(42-14i-6i-2) / (9+1}
= (40-20i)/10
= (20 - 10i)/ 5
= 4 - 2i
=============
Cheers,
Stan H.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
you multiply it by the conjugate of the denominator over itself
* = =
i^2 = -1, therefore
= =
Divide 10 into both terms
4 - 2i
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