SOLUTION: (2x - 1 )2 -4(2x -1)+ 2 =0
Not sure about my solution
Algebra.Com
Question 180885: (2x - 1 )2 -4(2x -1)+ 2 =0
Not sure about my solution
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.
Let (notice there are two terms that contain )
Plug in
Notice we have a quadratic equation in the form of where , , and
Let's use the quadratic formula to solve for z
Start with the quadratic formula
Plug in , , and
Negate to get .
Square to get .
Multiply to get
Subtract from to get
Multiply and to get .
Simplify the square root (note: If you need help with simplifying square roots, check out this solver)
Break up the fraction.
Reduce.
or Break up the expression.
So the answers (in terms of z) are or
However, we need the solutions in terms of "x". Remember, we let , so...
or Go back to the solutions (in terms of "z")
or Plug in
or Add 1 to both sides (for each equation).
or Combine like terms.
or Divide both sides by 2 (for each equation) to isolate "x".
===============================================================
Answer:
So the solutions are or
RELATED QUESTIONS
Not sure if this falls into the category of quadratics, but here's the question, if... (answered by jim_thompson5910)
What is the solution of |2x-7|+1 = 9
I get -3/2 but my answer key says -1/2
Not... (answered by macston)
I am confused on how you go about solving this substitution problem
4y+3=3y+x... (answered by mathsmiles,solver91311)
pls help!
this is about inequalities in algebra.
x/2+3/4 (answered by stanbon)
-2x^2-2x-1=0 (answered by srinivas.g)
Once again, I've got a solution that doesn't graph properly. My lines do not intersect.
(answered by rchill)
1. Complete thes ordered pairs for the equation 2y=-x-5:
(0,-5/4); (-3, -4); (-35, 15) I (answered by checkley75)
Find the value of "a" such that the equation ax^2 + 2x + 4 = 0 has exactly one solution.
(answered by ikleyn,Alan3354)
If point A = matrices 4 -4 -3 and B = 2 0 2 . Then find AB and BA
(answered by CPhill)