SOLUTION: Linear Systems Problem Solving 4. To run a 30-s ad during a weekday morning, one radio station charges a fixed cost of $400, plus $150 for each day the ad is run. A second radi

Question 180709: Linear Systems Problem Solving
4. To run a 30-s ad during a weekday morning, one radio station charges a fixed cost of $400, plus $150 for each day the ad is run. A second radio station charges a fixed cost of $300, plus $200/day. The costs can be modelled by the following equations, where C is the total cost and n is the number of days for which ad is run.
Station 1:C=150n+400
Station 2:C=200n+300
a) Find the missing element in the ordered pair ( , 700) that satisfies both equations and is in the form (n, C).
b) Explain what your ordered pair from part a) means for both radio stations.
c) Which station has the lower cost for running a 30-s ad for 5 weekday mornings? Hint: Find (5, ) for each equation.
Thankssssssssssssssssssssss alottttttttttttttt pleaseeeeeeeeeeeeeeeeeeeeeeeeeeee
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
a.)1.

N=2 satisifes both for C(N)=700.
.
.
.
b.)It means that if I run an ad on either station for 2 days it'll cost me $700.
.
.
.
c.)

Station 1's cost for a 5 day ad is $250 less than Station 2.
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