SOLUTION: y=1/1800(x-600)(x+600) x and y are measured in meters 1)how wide is the crater if y=0 and what is the depth of the crater?

Question 179785: y=1/1800(x-600)(x+600) x and y are measured in meters
1)how wide is the crater if y=0 and what is the depth of the crater?

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
:
y =(x-600)(x+600) x & y are measured in meters
:
1)how wide is the crater if y=0 and what is the depth of the crater?
:
Multiply equation by 1800
(x+600)(x-600) = 0
x = +600, x = -600
Difference between intercepts = 1200 meters
:
Find the min using the original equation
:
y =(x-600)(x+600)
:
y =
:
y = -
:
y =
:
difference of squares so axis of symmetry is 0
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in the above equation, y = -200, when x = 0
:
depth of the crater = 200 meters:
Like this

:
Crater is 1200 m wide and 200 m deep
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