SOLUTION: Arectangle 6 feet by 8 feet has a border of uniform width around the inside of all four edges. If the border has an area of 33 square feet, how wide is the border?

Question 179283: Arectangle 6 feet by 8 feet has a border of uniform width around the inside of all four edges. If the border has an area of 33 square feet, how wide is the border?
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
6*8=48 is the area of the rectangle.
(6+2x)(8+2x)=48+33
48+16x+12x+4x^2=81
4x^2+28x+48-81=0
4x^2+28x-33=0
Using them quadratic equation we get:
x=(-28+-sqrt[28^2-4*4*-33])/2*4
x=(-28+-sqrt[784+528)/8
x=(-28+-sqrt1312)/8
x=(-28+-36.22)/8
x=(-28+36.22)/8
x=(8.22)/8
x=1.0277
Proof:
(6+2*1.0277)(8+2*1.0277)=81
(6+2.055)(8+2.055)=81
8.055*10.055=81
81~81
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