SOLUTION: please solve each matriz.. 1. [3 4] [3] [-1 -1]x=[2] 2. [6 2] [8 1] [-1 4]-x [1 3] 3. x+[1 3 6] [8 1 0] [-1 2 1]= [14 3 -1] 4. [-3 -2] [8 -1] [1 1

Question 177941: please solve each matriz..
1. [3 4] [3]
[-1 -1]x=[2]

2. [6 2] [8 1]
[-1 4]-x [1 3]

3. x+[1 3 6] [8 1 0]
[-1 2 1]= [14 3 -1]

4. [-3 -2] [8 -1]
[1 1] x=[6 0]

5. 4x+3 [3 2] [10 8]
[1 -2]= [5 -2]

6. 2x=1/4[-6 2]
[8 -8]

Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!

I will do a few and let you do the rest
:
1. [3 4] [3]
[-1 -1]x=[2]
:
This is done with the assumption that you know how to multiply,add,and subtract matrices.
:
in this problem we have a 2x2 multiplied by a 2x1 and we of course get a 2x1 answer.
:
lets call our unknown matrix x=
so
:
=
:
3a-4b=3.....eq 1
-1a+b=2.....eq 2
:
so now we have a set of linear equations to solve
multiply eq 2 by 3 and add the two equations together. a terms will be eliminated because 3a-3a=0. We are left with -4b+3b=9
:
-b=9
:
b=-9
:
now plug this value into either eq
:
-1a+(-9))=2--->-a=2+9--->a=-11
:
so x=
:
3. x+[1 3 6] [8 1 0]
[-1 2 1]= [14 3 -1]
lets call x=
:
so +=
:
a+1=8--->a=7
b+3=1--->b=-2
c+6=0--->c=-6
d-1=14-->d=15
e+2=3--->e=1
f+1=-1-->f=-2
:
x=
:
hope that helps you on your way

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