SOLUTION: suppose a toy rocket was launched from the ground straight up with initial velocity of 64ft/sec. How many seconds after launch was the rocket 48 feet above the ground

Question 177484: suppose a toy rocket was launched from the ground straight up with initial velocity of 64ft/sec. How many seconds after launch was the rocket 48 feet above the ground
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The height function for this is where is the initial velocity and is the initial height. You are given that the initial velocity is ft/sec and the rocket was launched from the ground so .

So, and you want to solve for t when

→

Giving you a quadratic in t that can be solved by ordinary means. Note that you are going to get two different answers. Does that make sense? (Hint: What goes up, must come down)
RELATED QUESTIONS
The formula gives the height h in feet of an object after t seconds. Here is the... (answered by stanbon)

A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s... (answered by Boreal)

the formula h=vt-16t^2 gives the height h in feet of an object after t sec. Here v is the (answered by dabanfield,stanbon)

After t sec, the height of a rocket launched straight upward from the ground level with... (answered by ewatrrr)

hi, my question is following A toy rocket is launched straight up from the top of a... (answered by richwmiller)

a toy rocket is launched from a 144- foot cliff overlooking the ocean with an initial... (answered by jsmallt9)

A water rocket is launched upward with an initial velocity of 48 ft/sec. Its height h, in (answered by scott8148)

hi, my question is following A toy rocket is launched straight up from the top of a... (answered by Theo)

A toy rocket is launched from the ground with an initial velocity of 80 feet per second.... (answered by stanbon)