SOLUTION: Hi how would you solve this:
(x+8)^2-54=0
Thanks.
Algebra.Com
Question 177301: Hi how would you solve this:
(x+8)^2-54=0
Thanks.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.
Add 54 to both sides.
Take the square root of both sides.
or Break up the "plus/minus"
or Simplify the square root.
or Subtract 8 from both sides.
===========================================
Answer:
So the solutions are or
RELATED QUESTIONS
Hi, How would you solve this problem
(x-3)^2= 2x^2-7x-21... (answered by jim_thompson5910)
Hi guys, I was wondering whether anyone could help me to solve this quadratic equation... (answered by stanbon)
Hi,
would you pls, explain to me, how 2 do this:
Solve for x : 2x^2 – 5x = 12
I... (answered by alicealc)
Hi, I have a question. How would you solve this equation..... (answered by stanbon)
Hi. How do you solve this:(x+2)/(x-2)+ 4/(x-2) +... (answered by jim_thompson5910)
The area of a rectangle is 54 square units. Find the length and the width of the... (answered by checkley77)
How would you solve this x^2-12=0... (answered by checkley77)
Hi! How would you solve log base 2 of x + log base 2 of (x+3) = 2?
Thanks for your... (answered by scott8148)
hi I need a help on this question. Can you please explain it
if you continue the... (answered by ikleyn)