SOLUTION: I'm stuck on one part of deriving the quadratic equation. I can not figure out how x^2 + (b/a)x + (b/2a)^2 becomes (x + b/2a)^2. If I multiply this out I get x^2 + (b/2a)x + (b/2

Algebra.Com
Question 17667: I'm stuck on one part of deriving the quadratic equation. I can not figure out how x^2 + (b/a)x + (b/2a)^2 becomes (x + b/2a)^2. If I multiply this out I get x^2 + (b/2a)x + (b/2a)x + (b/2a)^2.
Thanks

Answer by mukku(2)   (Show Source): You can put this solution on YOUR website!
(a+b)^2 = a^2+b^2+2ab
Here a ix and b = b/2a
Substituting in the formula foe (a+b)^2 we get what you have in your problem

RELATED QUESTIONS

How do i solve this quadratic equation? x=^-b+√b^2-4ac... (answered by Fombitz)
ax^2-(2a+1)x+(a+1)=0 Then the product x1x2 is equal to: I know I have to use the... (answered by scott8148)
Doing a quadratic equation problem, i cam across a problem. the equation i got was... (answered by JimboP1977,solver91311)
Four steps to derive the quadratic formula are shown below. I x^2+(-b)/a x=(-c)/a II... (answered by ikleyn)
Problem: Find the inverse of {{{ y = x^2 + sqrt (x) }}}. I've fought the good fight,... (answered by ankor@dixie-net.com)
directions: use quadratic equation x=-b+(rad)(b^2-4ac)/2a to find theroots of the... (answered by ankor@dixie-net.com)
IN MY ALGEBRA 2 BOOK ON PAGE 296 I'M HAVING A HARD TIME UNDERSTANDING HOW I FIND THE... (answered by Earlsdon)
x^2/3-x-1/6 -b+-sqr rt of b^2-4ac/ 2a a=? b=-1 c=-1/6 I am stuck as to what "a"... (answered by Alan3354)
How many real numbers does the quadratic equation have 2x^2+7x+9=I Note use formula... (answered by MathLover1)