SOLUTION: Given x^3-4x^2+2x+1=0 A. How many possible negative roots are there? B. Using synthetic substitution, which of the possible rational roots is actually a root of the equation?

Algebra.Com
Question 176615: Given x^3-4x^2+2x+1=0
A. How many possible negative roots are there?
B. Using synthetic substitution, which of the possible rational roots is actually a root of the equation?

Answer by Mathtut(3670)   (Show Source): You can put this solution on YOUR website!
A) you must use f(-x) to find out the number of negative root possibles....f(-x)=-x^3-4x^2-2x+1=0
number of negative real roots is less than or equal to the number of variations in the function f (- x).
:
there is 1 variation in f(-x) therefore there is one negative real root
:
1 or -1 could be roots because they are factors of the constant which is 1
:
therefore 1 is a root
therefore -1 is NOT a root
:
This relationship is always true: If a polynomial has rational roots, then those roots will be fractions of the form (plus-or-minus) (factor of the constant term) / (factor of the leading coefficient). However, not all fractions of this form are necessarily zeroes of the polynomial. Indeed, it may happen that none of the fractions so formed is actually a zero of the polynomial.

since 1 is our constant and 1 is our leading coefficient the only possible rational roots are 1 divided by 1 or -1 which is the same as those terms we have already tested.
:
now synthetic division using the root 1 (x-1)
:
 
   |
  1|1 -4  2   1
   |___1_-3__-1___________________
    1 -3 -1   0
:

so when we factor out the root 1 we get
:

:and using the quadratic formula we get 2 irrational roots from this depressed equation
and

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=13 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 3.30277563773199, -0.302775637731995. Here's your graph:


RELATED QUESTIONS

Given x^3 - 4x^2 + 2x + 1 =0. b. How many possible negative roots are there? c. What... (answered by Mathtut)
Given x^3 - 4x^2 + 2x + 1 =0 (a)How many possible positive roots are there? (b)How... (answered by stanbon)
Hi, I need some help with my American School Algebra 2 work. Given X^*3-4x^*2+2x+1=0 A. (answered by Alan3354)
given x^3 - 4x^2 + 2x + 1= 0 (a)how many possible positive roots are there? (b)what are... (answered by solver91311)
Please help me. I'm stumped on 2 problems in Algebra 2. Here they are: 1. Find the... (answered by stanbon)
Could someone explain how I should solve these three problems; Use the synthetic... (answered by stanbon)
Could someone please help me out with this problem; which are the possible rational roots (answered by stanbon)
Id have a question; I should find out what the possible rational roots of x^3 - 4x^2... (answered by Alan3354)
given x^3-4x^2+2x+1=0 how many POSSIBLE POSITIVE AND NEGATIVE ROOTS ARE THERE. HOW MANY... (answered by richwmiller)