SOLUTION: The product of two consecutive even integers decreased by seven times the greater integer is 70. Find the two integers. I started the problem off this way: http://img229.images

Question 174924: The product of two consecutive even integers decreased by seven times the greater integer is 70. Find the two integers.
I started the problem off this way:
http://img229.imageshack.us/img229/8166/dtuyhsrxujt0.png
but now I'm lost, clearly. It looks like I'll be going into a degree of three, which doesn't make sense.
If you could perhaps show me where I went wrong, I'd really appreciate it. Thanks.
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
The product of two consecutive even integers decreased by seven times the greater integer is 70. Find the two integers.
.
Let x = 1st consecutive event integer
then
x+2 = 2nd consecutive even integer
.
x(x+2) - 7(x+2) = 70
x^2+2x - 7x-14 = 70
x^2- 5x-14 = 70
x^2- 5x-84 = 0
(x-12)(x+7) = 0
x = {12,-7}
Tossing out the odd solution, we're left with:
x = 12 (1st even integer)
.
x+2 = 12+2 = 14 (2nd even integer)
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