SOLUTION: how do i find how many real numbers the equation -4j^2+3j-28=0 has?

Question 174885: how do i find how many real numbers the equation -4j^2+3j-28=0 has?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
To find the number of real solutions, we can use the discriminant formula.

From we can see that , , and

Start with the discriminant formula.

Plug in , , and

Square to get

Multiply to get

Subtract from to get

Since the discriminant is less than zero, this means that there are two complex solutions. In other words, there are no real solutions.

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