SOLUTION: Find the vertex, axis, and the x & y intercepts of
y= (2x-7) (2x-1)
please explain step by step
I would really appreciate any help!
Algebra.Com
Question 172897: Find the vertex, axis, and the x & y intercepts of
y= (2x-7) (2x-1)
please explain step by step
I would really appreciate any help!
Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!
Expand:
Transpose constant to the left, likewise "copy" the "a" constant of a quadratic eqn --->to the left. factor out the right term:
Complete the square by taking "half" of '4' on the right term,in this ---> , then squared it---->.
--> it follows vertex form,
where--->
So, therefore, the vertex is at (2,-9).
Axis of symmetry is the x-intercept of the vertex: --->
For Y-Intercept:
For the X-Intercepts: We solve the eqn:
------>
---->
As you see in the graph:
---->Vertex (2,-9)
Thank you,
Jojo
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