SOLUTION: help! Find zeros for the function: g(x) = 6 - x^2 -5x h(x) = x^2 + 6x + 12

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Question 172630: help!
Find zeros for the function:
g(x) = 6 - x^2 -5x
h(x) = x^2 + 6x + 12
Answer by KnightOwlTutor(293)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=1 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: -3, -2. Here's your graph:

Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -12 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -12 is + or - .

The solution is

Here's your graph:
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