SOLUTION: Here is the problem: y=-2x^2+8x-5 Here is what I tried: h=-(8/2(-2)) -2(2)^2-8(2)-5 -8-16-5 ... This doesn't make sense, because the y value seems too large. Am I doing th

Question 172109: Here is the problem: y=-2x^2+8x-5
Here is what I tried:
h=-(8/2(-2))
-2(2)^2-8(2)-5
-8-16-5
...
This doesn't make sense, because the y value seems too large.
Am I doing this problem correctly?
Thanks!

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Here is the problem: y=-2x^2+8x-5
Here is what I tried:
h=-(8/2(-2))
-2(2)^2-8(2)-5
-8-16-5
...
This doesn't make sense, because the y value seems too large.
Am I doing this problem correctly?
-----------------
I think you want to find the values of x in:
-2x^2+8x-5 = 0
If so:
2x^2-8x+5 = 0

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=24 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 3.22474487139159, 0.775255128608411. Here's your graph:

Ignore the factors, it's not right. The answers are:
2+sqrt(6)/2
2=sqrt(6)/2

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