SOLUTION: Find the vertex for the graph of the quadratic function. (f)x= x^2 -13

Question 171912: Find the vertex for the graph of the quadratic function.
(f)x= x^2 -13
Found 2 solutions by jim_thompson5910, checkley77:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

In order to find the vertex, we first need to find the x-coordinate of the vertex.

To find the x-coordinate of the vertex, use this formula: .

Start with the given formula.

From , we can see that , , and .

Plug in and .

Multiply 2 and to get .

Divide.

So the x-coordinate of the vertex is . Note: this means that the axis of symmetry is also .

Now that we know the x-coordinate of the vertex, we can use it to find the y-coordinate of the vertex.

Start with the given equation.

Plug in .

Square to get .

Combine like terms.

So the y-coordinate of the vertex is .

So the vertex is .

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
(f)x=x^2-13
(graph 300x200 pixels, x from -6 to 5, y from -15 to 10, x^2 -13).
Vertex=(0,-13)
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