SOLUTION: given the equation Kx^2+(k+3)x+3-4k=0 find the value of k given that one root is 2

Question 171658: given the equation Kx^2+(k+3)x+3-4k=0 find the value of k given that one root is 2
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let ,

If one root is 2, then this means that and

Start with the given equation.

Plug in .

Square 2 to get 4.

Distribute.

Set the right side equal to zero.

Combine like terms on the left side.

Subtract from both sides.

Combine like terms on the right side.

Divide both sides by to isolate .

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Answer:

So the answer is which in decimal form is .
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