SOLUTION: Can you please show me how to graph each quadratic equation using its properties, and also based on the graph, determine the domain and range of the quadratic function. I am los

Question 171579: Can you please show me how to graph each quadratic equation using its properties, and also based on the graph, determine the domain and range of the quadratic function.
I am lost when it comes to this new chapter we have started...
F(x) = -x^2 + 2x + 8
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
In order to graph , we can follow the steps:

Step 1) Find the vertex (the vertex is the either the highest or lowest point on the graph)

Step 2) Once you have the vertex, find two points on the left side of the axis of symmetry (the line that vertically runs through the vertex)

Step 3) Reflect the points over the axis of symmetry to get two more points on the right side of the parabola (remember a parabola is symmetric).

Step 4) Plot all of the points found (including the vertex)

Step 5) Draw a curve through all of the points to graph the parabola

Let's go through these steps in detail

Step 1)

Finding the vertex:

In order to find the vertex, we first need to find the x-coordinate of the vertex.

To find the x-coordinate of the vertex, use this formula: .

Start with the given formula.

From , we can see that , , and .

Plug in and .

Multiply 2 and to get .

Divide.

So the x-coordinate of the vertex is . Note: this means that the axis of symmetry is also .

Now that we know the x-coordinate of the vertex, we can use it to find the y-coordinate of the vertex.

Start with the given equation.

Plug in .

Square to get .

Multiply and to get .

Multiply and to get .

Combine like terms.

So the y-coordinate of the vertex is .

So the vertex is

.

------------------------------------------------------------------------------------

Step 2)

Find two points to the left of the axis of symmetry:

Lets find the value of y when x=-1

Start with the given polynomial

Plug in

Square 1 to get 1

Multiply 2 by -1 to get -2

Now combine like terms

So our 1st point is (-1,5)

----Now lets find another point----

Lets find the y value when x=0

Start with the given polynomial

Plug in

Square 0 to get 0

Multiply 2 by 0 to get 0

Combine terms

So our 2nd point is (0,8)

------------------------------------------------------------------------------------

Step 3)

Reflecting the two points over the axis of symmetry:

Now remember, the parabola is symmetrical about the axis of symmetry (which is )

This means the y-value for is equal to the y-value of . So when , . So we've reflected the point (0,8) over to (2,8)

Also, the y-value for is equal to the y-value of . So when , . So we've reflected the point (-1,5) over to (3,5)

------------------------------------------------------------------------------------

Step 4)

Plotting the points:

Now lets make a table of the values we have calculated

Now let's plot the points:

------------------------------------------------------------------------------------

Step 5)

Drawing a curve through all of the points:

Now draw a curve through all of the points to graph :

Graph of

From the graph, we can determine the following:

Domain: All real numbers

Range:
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