SOLUTION: How do you convert functions standard form to vertex form? Problem: y= x2-4x=6

Question 170146This question is from textbook prentice hall mathematics California algebra 2
: How do you convert functions standard form to vertex form?
Problem: y= x2-4x=6 This question is from textbook prentice hall mathematics California algebra 2

Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do you convert functions standard form to vertex form?
Problem: y= x^2-4x+6
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Complete the square with the x terms:
x^2-4x+4 = y-6+4
(x-2)^2 = y-2
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This shows you the vertex is at (2,2) and p= 1/4
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Cheers,
Stan H.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the right side of the equation.

Take half of the coefficient to get . In other words, .

Now square to get . In other words,

Now add and subtract . Make sure to place this after the "x" term. Notice how . So the expression is not changed.

Group the first three terms.

Factor to get .

Combine like terms.

So after completing the square, transforms to . So .

So is equivalent to .

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Answer:

So the equation in vertex form is

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