SOLUTION: I am trying to solve y=x2-6x. so far column x is 0 1 2 3 4 column y is 0 -5 -8 a=1 b=-6 c=0. At school I understood where to get these #s now im lost. not sure how i need to do

Question 168430: I am trying to solve y=x2-6x. so far column x is 0 1 2 3 4 column y is 0 -5 -8 a=1 b=-6 c=0. At school I understood where to get these #s now im lost. not sure how i need to do this
Answer by KnightOwlTutor(293) (Show Source): You can put this solution on YOUR website!
This is a quadratic equation ax^2+bx+c=0
In your equation a=1 b=-6 and c=0
The y column is the value of y at the indicated x value.

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=36 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 6, 0. Here's your graph:

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