SOLUTION: How would I complete the square for both x and y and find the equation of the circle for the given equation x^2-8x+y^2+4y-205=0. I also have the same question for the following equ

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Question 167715: How would I complete the square for both x and y and find the equation of the circle for the given equation x^2-8x+y^2+4y-205=0. I also have the same question for the following equation x^2+12x+y^2-14y-204=0.
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
I'll do the first (which hopefully will help you do the second)


# 1




Start with the given equation


Add to both sides


Complete the square for the "x" terms. Note: Let me know if you need help completing the square.


Complete the square for the "y" terms


Combine like terms


Add to both sides


Combine like terms




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Notice how the equation is now in the form . This means that this conic section is a circle where (h,k) is the center and is the radius.

So the circle has these properties:

Center: (4,-2)

Radius:
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