SOLUTION: 2x^2-3x+1=0 Solve by completing the square.

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Question 166950: 2x^2-3x+1=0
Solve by completing the square.
Found 2 solutions by nerdybill, Edwin McCravy:
Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!
2x^2-3x+1=0
2x^2-3x = -1
2(x^2 - (3/2)x) = -1
2(x^2 - (3/2)x + 9/16) = -1 + 9/8
2(x-(3/4))^2 = -8/8 + 9/8
2(x-(3/4))^2 = 1/8
(x-(3/4))^2 = 1/16
x-(3/4) = (+-)1/4
x = (3/4)(+-)1/4
.
x = {2/4, 4/4}
x = {1/2, 1}
Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!
Edwin's solution:




Isolate the variable terms by
adding -1 to both sides:



Divide thru by 2, the coefficient of the 
term in 





To the side, multiply the coefficient of x by .


Now square .  

Add  to both sides of



Combine the right side: 



Factor the left side:



Write the left side as the square of
a binomial:



Take the square root of both sides,
remembering the ± on the right:



=±



Using the +





Using the -





The solutions are  and 

Edwin
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