SOLUTION: x^2-6x=16
Solve by completing the square.
this is what I did...but it isn't the correct way to do it.
(x-8)(x+2)
x=8, x=-2
Algebra.Com
Question 166949: x^2-6x=16
Solve by completing the square.
this is what I did...but it isn't the correct way to do it.
(x-8)(x+2)
x=8, x=-2
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
This site explains the entire process:
http://www.purplemath.com/modules/sqrquad.htm
.
x^2-6x=16
Divide the -6 by 2 and square it to get 9. Add it to both sides:
x^2-6x+9=16+9
(x-3)^2 = 25
take the square root of both sides:
x-3 = (+-)5
x = 3(+-)5
.
x = {-2, 8}
RELATED QUESTIONS
Two verticies of a rectangle are on the x-axis and the other two vertices on the curve... (answered by ikleyn)
Solve by completing the square.
{{{ x^2 + 6x + 4 = 0 }}}
I thought I was doing the... (answered by Nate)
It asks to solve by completing the square, the problem is: x^2-6x=16
Please and Thank... (answered by MathLover1)
Solve by completing the square. x^2+6x=-8
(answered by nerdybill)
The question asks to solve the problem using the square root method: (x-1)^2=16
I have... (answered by rothauserc,MathTherapy)
{{{X^2-6x=16}}} I'm supposed to solve this by completing the... (answered by longjonsilver)
I need to solve x^2+6x-16=0 by completing the... (answered by jim_thompson5910)
Solve by completing the square
{{{x^2+8 x=-15}}} (answered by jim_thompson5910)
I dont understand how to solve this problem:
Original Equation:
[(x)/(x-3)] -... (answered by richwmiller)