SOLUTION: the perimeter of a square and a rectangle are equal. The length of the rectangle is 11cm and area of the square is 4cm^2 more than the area of the rectangle.find the side of the sq
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Question 165927: the perimeter of a square and a rectangle are equal. The length of the rectangle is 11cm and area of the square is 4cm^2 more than the area of the rectangle.find the side of the square?
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
Let x= square's side
Let y=length of the rectangle
Let z=width of the rectangle
the perimeter of a square and a rectangle are equal
then 4x=2(y+z)
The length of the rectangle is 11cm
then y=11
area of the square is 4cm^2 more than the area of the rectangle
so the system to solve is:
then
then
then
then
x=13 or x=9
if x=9 then z=18-11=7
if x=13 then z=26-11=15
then z=7 or z=15 but z
Answer: x=9,z=7 and y=11
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