SOLUTION: Please help me set up these equations and solve. Thank you in advance.
4. A cell divides into two identical copies every 4 minutes. How many cells will exist after 3 hours?
5
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Question 165015This question is from textbook elementary and intermediate algebra
: Please help me set up these equations and solve. Thank you in advance.
4. A cell divides into two identical copies every 4 minutes. How many cells will exist after 3 hours?
5. The level of thorium in a sample decreases by a factor of one-half every 4.2 million years. A meteorite is discovered to have only 7.6% of its original thorium remaining. How old is the meteorite?
This question is from textbook elementary and intermediate algebra
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
4. A cell divides into two identical copies every 4 minutes. How many cells will exist after 3 hours?
:
Find the number of 4 min periods in 3 hrs: 180/4 = 45
a lot of cells in 3 hrs
:
5. The level of thorium in a sample decreases by a factor of one-half every 4.2 million years. A meteorite is discovered to have only 7.6% of its original thorium remaining. How old is the meteorite?
:
The decay formula: Ao*2^(-t/h) = A
Where:
Ao = initial amt
A = resulting amt
t = time (in millions of yrs)
h = half-life of the substance (in millions of years)
:
In this problem: let Ao = 1; A = .076
1*2^(-t/4.2) = .076
:
ln(2^(-t/4.2)) = ln(.076); find the nat log of both sides
:
.693 = -2.577; use the log equiv of exponents
:
= -2.577;
Multiply both sides by 4.2
-.693t = -2.577 * 4.2
:
-.693t = -10.823
t =
t = 15.6 million years old
;
:
Check solution on a calc enter 2^(-15.6/4.2) = .076..
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