SOLUTION: Solve {{{sqrt(2x+1)+3=10}}} Note 2x+1 is under the radical sign and the +3 is not

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: Solve {{{sqrt(2x+1)+3=10}}} Note 2x+1 is under the radical sign and the +3 is not      Log On

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Question 164238: Solve sqrt%282x%2B1%29%2B3=10
Note 2x+1 is under the radical sign and the +3 is not
Answer by aka042(26) About Me  (Show Source):
You can put this solution on YOUR website!
First let's move the constant that is not in the square root to the right side: sqrt%282x%2B1%29+=+7. Now let's square both sides %28sqrt%282x%2B1%29%29%5E2+=+7%5E2 => 2x%2B1+=+49. Now we combine like terms and solve for x: 2x+=+48 => +x+=+48%2F2+=+24.