SOLUTION: I am having a really hard time with this problem! Please show me how it should be solved! Thank you in advance! If the path of a frog's jump is approximated by the equation

Question 162945: I am having a really hard time with this problem! Please show me how it should be solved! Thank you in advance!
If the path of a frog's jump is approximated by the equation y = -0.25x^2 + 5x, what is the height of the frog's jump?

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
How high did the frog jump?

This is a quadratic equation and, when graphed, you will see a parabola that opens downward. The dependent variable (y) represents the height of the frog's jump at time (x) seconds.
You may see this kind of equation written as:

The vertex of the parabola is, of course, a maximum, and this represents the maximum height of the frog's jump.
So you need to find the coordinates of the vertex.
The x-coordinate of the vertex is given by: where the a and b come from the general form of the equation:
In your problem, a = -0.25 and b = 5, so...

now substitute this value of x into the original quadratic equation to find the corresponding y-coordinate.
Simplify and solve for y.

The frog's maximum height is 25 feet.

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