SOLUTION: pls.help me solve the following quadratic equation by factoring: {{{2x^2-3x+1=0}}} {{{4x^2+9x=9}}} {{{2y^2+y=-11y}}} {{{y^2-7-44=0}}} {{{6x^2+11x-1=0}}} pls. submit your

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Question 162005: pls.help me solve the following quadratic equation by factoring:





pls. submit your answer as soon as possible i need to pass it tomorrow
im begging you pls..
Found 2 solutions by KnightOwlTutor, scott8148:
Answer by KnightOwlTutor(293)   (Show Source): You can put this solution on YOUR website!

We know that the last term must be 1
Set up the equation like this
it could be -1,-1 or 1,1
Because you have a negative middle term it is most likely -1,-1
(2x-1)(x-1)=0
Therefore the solution is x= 1/2 or 1 we need to make the equation=0 and the only way to accomplish this is to make one or both terms =0




We need to subtract 9 from both sides of the equation
4x^2+9x-9=0
We need to find two numbers that have a product of 9 the possibilities are 3,3
9,1
We have a negative number so we know that the product is -
We then need to know what 2 numbers give a product of 4
2,2 or 4,1
Let's set up the equation
using 3,3
(_x-3)(_x+3)
The middle terms need to add up to 9x Let's try 4 and 1
(4x-3)(x+3) The middle term for this problem is -3x+12x=9x
We have the correct factors
the solution is x=3/4 or -3



Here we add 11y to both sides of the equation
2y^2+y+11y=0
2y^2+12y=0
factor out 2
2(y^2+6)=0
y=sqrt6 i
remember that i=sqrt of -1


First we try to calculate the numbers that generate a product of 44
4,11 or 44,1
Let's try 4,11
(y-11)(y+4)
y =11 or -4

6x^2+11x-1=0
ax^2+bx+c=0 a=6 b=11 c=-1
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=145 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 0.0867995482326913, -1.92013288156602. Here's your graph:





Use the quadratic formula
Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!
2x^2-3x+1=0 __ (2x-1)(x-1)=0

4x^2+9x=9 __ 4x^2+9x-9=0 __ (4x-3)(x+3)=0

2y^2+y=-11y __ 2y^2+12y=0 __ 2y(y+6)=0

y^2-7-44=0 __ y^2-51=0 __ (y+sqrt(51))(y-sqrt(51))=0

6x^2+11x-1=0 __ not factorable
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