SOLUTION: Could someone please show me how to get the line of symentry, vertex and the min/max of the line. {{{f(x)=(1/4)(x+2)^2+2}}}

Question 160400: Could someone please show me how to get the line of symentry, vertex and the min/max of the line.

Found 2 solutions by Earlsdon, scott8148:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Find the line of symmetry (sp!), vertex, and the min. or max. of the curve:

Your quadratic equation is already written in the "vertex" form of: where the vertex is located at the point (h, k), so you can write the coordinates of the vertex directly from your equation: (h = -2 and k = 2)
Vertex is at (-2, 2)
The line of symmetry is the vertical line that passes through the point x = -2, so the equation of the line of symmetry is: .
The parabola represented by your equation open upwards which you can tell because the coefficient of i.e. () is positive, so the vertex is a minimum.
See the graph below:

Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
this eqn is in the form y=a(x-h)^2+k (sometimes called the "vertex form")

the vertex is (h,k)

the axis of symmetry is x=h

the min/max is the vertex __ min if a is positive __ max if a is negative
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