SOLUTION: x^2/3-x-1/6 -b+-sqr rt of b^2-4ac/ 2a a=? b=-1 c=-1/6 I am stuck as to what "a" is.

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Question 159121: x^2/3-x-1/6 -b+-sqr rt of b^2-4ac/ 2a
a=? b=-1 c=-1/6
I am stuck as to what "a" is.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
x^2/3-x-1/6 -b+-sqr rt of b^2-4ac/ 2a
a=? b=-1 c=-1/6
I am stuck as to what "a" is.
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If it's , then a = 1/3
To solve it, multiply by 6
2x^2 - 6x - 1 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=44 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 3.1583123951777, -0.1583123951777. Here's your graph:

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The onsite solver doesn't handle the coefficients well, but you can figure it out from what's shown.

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