SOLUTION: I've been working on an assignment and I'm stumped. I have to solve quadratic equations with the following steps: a) Move the constant term to the right side of the equation. b)

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Question 157876: I've been working on an assignment and I'm stumped. I have to solve quadratic equations with the following steps:
a) Move the constant term to the right side of the equation.
b) Multiply each term in the equation by four times the coefficient of the x2 term.
c) Square the coefficient of the original x term and add it to both sides of the equation.
d) Take the square root of both sides.
3) Set the left side of the equation equal to the positive square root of the number on the right side and solve for x.
f) Set the left side of the equation equal to the negative square root of thenumber on the right side of the euqation and solve for x.
I have two equations I'm stuck on:
1) x2 - 2x - 13 = 0
2) 2x2 - 3x - 5 = 0

Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!
a) Move the constant term to the right side of the equation.
1)

b) Multiply each term in the equation by four times the coefficient of the term.
the coefficient of the is and four times the coefficient will be , so you will have:


c) Square the coefficient of the original term and add it to both sides of the equation.
the coefficient of the original term is

…then you have


d) Take the square root of both sides.
= +-
= +-

e) Set the left side of the equation equal to the positive square root of the number on the right side and solve for .






f) Set the left side of the equation equal to the negative square root of the number on the right side of the equation and solve for .







2)
a) Move the constant term to the right side of the equation.

b) Multiply each term in the equation by four times the coefficient of the term.
the coefficient of the is and four times the coefficient will be , so you will have:



c) Square the coefficient of the original term and add it to both sides of the equation.
the coefficient of the original term is





d) Take the square root of both sides

= +-

e) Set the left side of the equation equal to the positive square root of the number on the right side and solve for .
= +





f) Set the left side of the equation equal to the negative square root of the number on the right side of the equation and solve for .
= -





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