SOLUTION: 3x^3-24
Since 24 is not a perfect cube I think I factor out the 3 as follows:
3(x^3-8)
Am I on the right track?
Algebra.Com
Question 156799: 3x^3-24
Since 24 is not a perfect cube I think I factor out the 3 as follows:
3(x^3-8)
Am I on the right track?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Yes.
.
After pulling out the 3, the remainder is a "difference of cubes" -- now, you can apply "special factoring".
.
See:
http://www.purplemath.com/modules/specfact2.htm
for detailed information
.
3(x^3-8)
3(x-2)(x^2 + 2x + 2^2)
3(x-2)(x^2 + 2x + 4)
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