SOLUTION: Find the value of a such that the line y=x^2+a has exactly one intersection point with the parabola with equation y=x^2+3x+2.

Question 156380: Find the value of a such that the line y=x^2+a has exactly one intersection point with the parabola with equation y=x^2+3x+2.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the value of a such that the line y=x^2+a has exactly one intersection point with the parabola with equation y=x^2+3x+2.
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I see only one intersection of the 2 parabolas for any value of a.
You said "line y=x^2+a", but that's a parabola. Did you mean y = x+a?
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