SOLUTION: Solve 15x^4-31x^2+10=0 The solution of x= ??

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Question 156148: Solve
15x^4-31x^2+10=0
The solution of x= ??

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Let . So . In short,

Start with the given equation


Plug in and



Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for z:


Starting with the general quadratic





the general solution using the quadratic equation is:







So lets solve ( notice , , and )





Plug in a=15, b=-31, and c=10




Negate -31 to get 31




Square -31 to get 961 (note: remember when you square -31, you must square the negative as well. This is because .)




Multiply to get




Combine like terms in the radicand (everything under the square root)




Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




Multiply 2 and 15 to get 30


So now the expression breaks down into two parts


or


Lets look at the first part:





Add the terms in the numerator

Divide


So one answer is






Now lets look at the second part:





Subtract the terms in the numerator

Divide


So another answer is




So our solutions are:

or






Remember, we let . So this means that


or


Take the square root of both sides for each case (remember the "plus/minus")


, , , or



Rationalize the denominator (if necessary)

, , , or


--------------------------------------
Answer:

So the solutions are

, , , or

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