SOLUTION: Hi, I tried to solve the following problem and this is what I got can someone tell me if its right? 1. 3^1/2(y)^2-4y-(3)^1/2=0 Which is our graphical form 3^1/2y^2-4y-(7(

Question 154374: Hi,
I tried to solve the following problem and this is what I got can someone tell me if its right?
1. 3^1/2(y)^2-4y-(3)^1/2=0
Which is our graphical form 3^1/2y^2-4y-(7(3)^1/2=0

simplifies to 3/2y^2-4*y-21/2=0
Explanation:
Look at 3^1/2y^2-4y-(7(3)^1/2=0

Replace constants in factor: 3 ,1 with 3
It becomes 3/ 2*y^2 -4y 7*3^1/2=0

Look at 3/ 2*y^2 -4y 7*3^1/2=0.
Replace constants in factor: {3},1 with 3
It becomes: 3/2*y^2 -4y -7*3/2 =0
Look at: 3 /2*y^2 -4y -7*3/2 =0
Multiplied numerator integers 7*3 to get 21
It becomes 3 /2*y^2 -4y -21/2 =0
Result: 3 / 2*y^2 -4y -21/2=0
Again, I sorry for the trouble I am causing thank you so much for your help.
Jimmy

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I don't know what to make of your work, but here's the way that I would do it:

Start with the given equation.

Rewrite as

Notice we have a quadratic equation in the form of where , , and

Let's use the quadratic formula to solve for y

Start with the quadratic formula

Plug in , , and

Negate -4 to get 4

Square 4 to get 16

Multiply and to get

Multiply -4 and -3 to get 12

Add

Simplify the square root

or Break up the "plus/minus"

or Multiply both numerator and denominator by to rationalize the denominator

or Combine the fractions

or Multiply

or Multiply again

or Distribute

or Multiply

or Reduce

================================================================

Answer:

So the solutions are or

which approximate to or

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