SOLUTION: this is not in a text book 400(x-1)^2=225 this is what I have 400x^2-800x+175=0 my instructions are solve for x x= -(-800) +/- sqrt[(-800)^2

SOLUTION: this is not in a text book 400(x-1)^2=225 this is what I have 400x^2-800x+175=0 my instructions are solve for x x= -(-800) +/- sqrt[(-800)^2 - 4(400*175)]/2(400) x= [800+/- s

Question 154198: this is not in a text book
400(x-1)^2=225
this is what I have
400x^2-800x+175=0
my instructions are solve for x
x= -(-800) +/- sqrt[(-800)^2 - 4(400*175)]/2(400)
x= [800+/- sqrt(640000-280000)] / 800
x= (800 +/- sqrt 360,000) /800
x= (800 +/- 1.000000001)/800
is it right up to this point? where do we go from here?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given equation.

Divide both sides by .

Reduce.

Take the square root of both sides.

or Break up the "plus/minus" to form two equations.

or Take the square root of to get .

or Add to both sides.

or Combine like terms.

--------------------------------------

Answer:

So the solutions are or .
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