SOLUTION: In a complex number system, any quadratic equation has either one or two solutions. (That is the T/F question) I believe this is false because I thought they will always have 2

Question 151469: In a complex number system, any quadratic equation has either one or two solutions. (That is the T/F question)
I believe this is false because I thought they will always have 2 solutions but can someone explain if I am wrong?

Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
It is TRUE.
.
Consider the quadratic equation:

.
Notice that we get our TWO solutions of a quadratic from the +- portion.
.
Now, let's focus our attention on (the term after the +-):

.
Notice that if:
b^2 is EQUAL to 4ac we will be taking the square root of zero. In this case,
we will get only one solution:

.
As an example, consider this:
x^2+2x+1 = 0
factoring we get:
(x+1)(x+1) = 0
Notice that we ONLY have a single solution of:
x = -1

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