SOLUTION: Help!!! I have no idea how to solve these problems...... Solve: 2x*(x+3) = x+25 and 3x*(x+3) = 2*(5x+1) and (x^2-2x)(x+3) = -2x(x+1)

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Question 150585: Help!!! I have no idea how to solve these problems......
Solve: 2x*(x+3) = x+25
and
3x*(x+3) = 2*(5x+1)
and
(x^2-2x)(x+3) = -2x(x+1)
Found 2 solutions by edjones, Earlsdon:
Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
2x(x+3) = x+25
2x^2+6x=x+25
2x^2+5x-25=0
2*-25=-50 what two factors of -50 when added equal 5? 10 and -5
2x^2+10x-5x-25=0
2x(x+5)-5(x+5)=0
(x+5)(2x-5)=0
x=-5,
2x=5 x=5/2
.
3x(x+3) = 2(5x+1)
3x^2+9x=10x+2
3x^2-x-2=0
3*-2=-6 what two factors of -6 when added equal -1? 2 and -3
3x^2+2x-3x-2=0
x(3x+2)-(3x+2)=0
(x-1)(3x+2)=0
x=1
3x=-2 x=-2/3
.
(x^2-2x)(x+3) = -2x(x+1)
x^3+x^2-6x=-2x^2-2x
x^3+3x^2-4x=0
x(x^2+3x-4)=0
x(x+4)(x-1)=0
x=0, x=-4, x=1
.
Ed


Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
Solve for x:
1) First, perform the indicated distributive property on the left side.
Now combine like-terms by subtracting x from both sides.
Then subtract 25 from both sides.
Now you have a quadratic equation in standard form that can be solved by factoring.
Apply the zero product rule.
or
If then and
If then
The solutions are:


2) First, perform the indicated distributive property on both sides.
Now combine like-terms by subtracting 10x from both sides.
Then subtract 2 from both sides.
Now you have a quadratic equation that can be solved by factoring.
Apply the zero product rule.
or
If then and
If then
The solutions are:


Now this should give you enough clues to do the third problem.
If you still have difficulty then please re-post.
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