SOLUTION: 3x^2+19x-14=0 then I have to write it in the quadratic formula. -19+-sqrt(-19^2-4*3*-14/2*19; x=19+sqrt361+168/38; 19+-sqrt529/38; x=19+-23/38; x=42/38=6/2; x=6/2=-4 I got the -4 s

SOLUTION: 3x^2+19x-14=0 then I have to write it in the quadratic formula. -19+-sqrt(-19^2-43-14/2*19; x=19+sqrt361+168/38; 19+-sqrt529/38; x=19+-23/38; x=42/38=6/2; x=6/2=-4 I got the -4 s

Question 150123This question is from textbook
: 3x^2+19x-14=0 then I have to write it in the quadratic formula. -19+-sqrt(-19^2-4*3*-14/2*19; x=19+sqrt361+168/38; 19+-sqrt529/38; x=19+-23/38; x=42/38=6/2; x=6/2=-4 I got the -4 sub 19 from 23 to get the -4. Can you please tell me if this is right because there is alot of steps to this thank you. This question is from textbook

Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Yes, there are a lot of steps.
You started out with a mistake in the denominator, 19 instead of 3.

and made a minor mistake along the way.

You lost the negative sign in front of 19.

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First solution

Answer in lowest terms
Second solution

Answer in lowest terms
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I'm not sure about x=6/2=-4??
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Remember you can always check your answer by plugging it back into the equation.

Good answer.
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