SOLUTION: What three techniques can be used to solve quadratic equations? Demonstrate these techniques on the equation 12x^2-10x-42=0.

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Question 149608: What three techniques can be used to solve quadratic equations? Demonstrate these techniques on the equation 12x^2-10x-42=0.
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Technique #1 Factoring:

First let's factor


Start with the given expression


Factor out the GCF


Now let's focus on the inner expression

------------------------------------------------------------

Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .


Now multiply the first coefficient by the last term to get .


Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?


To find these two numbers, we need to list all of the factors of (the previous product).


Factors of :
1,2,3,6,7,9,14,18,21,42,63,126
-1,-2,-3,-6,-7,-9,-14,-18,-21,-42,-63,-126


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to .
1*(-126)
2*(-63)
3*(-42)
6*(-21)
7*(-18)
9*(-14)
(-1)*(126)
(-2)*(63)
(-3)*(42)
(-6)*(21)
(-7)*(18)
(-9)*(14)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient :


First NumberSecond NumberSum
1-1261+(-126)=-125
2-632+(-63)=-61
3-423+(-42)=-39
6-216+(-21)=-15
7-187+(-18)=-11
9-149+(-14)=-5
-1126-1+126=125
-263-2+63=61
-342-3+42=39
-621-6+21=15
-718-7+18=11
-914-9+14=5



From the table, we can see that the two numbers and add to (the middle coefficient).


So the two numbers and both multiply to and add to


Now replace the middle term with . Remember, and add to . So this shows us that .


Replace the second term with .


Group the terms into two pairs.


Factor out the GCF from the first group.


Factor out from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


Combine like terms. Or factor out the common term


So factors to


Set the factored expression equal to zero


Now set each factor equal to zero:

or

or Now solve for x in each case


So our answers are

or








Technique #2 Quadratic Formula:



Start with the given equation.


Let's use the quadratic formula to solve for x


Start with the quadratic formula


Plug in , , and


Negate to get .


Square to get .


Multiply to get


Rewrite as


Add to to get


Multiply and to get .


Take the square root of to get .


or Break up the expression.


or Combine like terms.


or Simplify.


So our answers are or





Technique # 3 Completing the square


Start with the given expression


Factor out the leading coefficient


Take half of the x coefficient to get (ie ).

Now square to get (ie )




Now add and subtract this value inside the parenthesis. Notice how . Since we're adding 0, we're not changing the equation.



Now factor to get


Combine like terms


Distribute


Multiply



So after completing the square, becomes .


So is equivalent to


Start with completed square equation.



Add to both sides.


Divide both sides by 12.


Take the square root of both sides.


or Break up the expression


or Take the square root of to get



or Subtract from both sides.


or Combine like terms and simplify.


So the answers are or







Technique # 4 Graphing

Simply graph to get


Graph of


Now use the calculator's zero function to find the zeros at and

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