SOLUTION: The problem is to solve the quadratic equation using the Indian method of multiplying each term in the equation by four times the coefficient of the x sqrt 2 term. The equation is

Question 148747: The problem is to solve the quadratic equation using the Indian method of multiplying each term in the equation by four times the coefficient of the x sqrt 2 term.
The equation is 2x^2 - 3x - 5 = 0
This class is killing me. Please help
Ellen

Answer by mangopeeler07(462) (Show Source): You can put this solution on YOUR website!
Dear Ellen,

Traditional method:
=0
First factor it out:

Start with
(2x )(x )

Then notice that everything after is negative so
(2x- )(x+ )

Then insert two factors of 5 (the only two would be 5 and 1):
(2x-5)(x+1)

Set each set of parentheses equal to 0:
(2x-5)=0
(x+1)=0

Solve for x in both:
2x-5=0
2x=5
x=5/2

x+1=0
x=-1

So x=5/2; -1
--------------------------------------------------------------------------------
Indian method:
=0
Multiply the whole thing by 4(2) or 8:
=0
Factor

Set each expression equal to zero and solve
(4x-10)=0
4x=10
x=10/4
Reduce
x=5/2

(4x+4)=0
4x=-4
x=-1

So x=5/2; -1

Sincerely,
Alani

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