SOLUTION: I need to solve using quadratic formula 2x^2-3x=-6 the solution set is { }
what I am coming up with is
-(-3)+-sqrt57/4
but I am stuck after that
any help would be appreciated
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Question 147088: I need to solve using quadratic formula 2x^2-3x=-6 the solution set is { }
what I am coming up with is
-(-3)+-sqrt57/4
but I am stuck after that
any help would be appreciated! Thank you
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I need to solve using quadratic formula 2x^2-3x=-6 the solution set is { }
what I am coming up with is
-(-3)+-sqrt57/4
but I am stuck after that
------------------------------
2x^2-3x=-6
2x^2-3x+6 = 0
a = 2 ; b = -3 ; c = 6
---------
x = [3 +- sqrt(3 -4*2*6]/4
x = [3 +- sqrt(-45)]/4
x = [3 +- 3isqrt(5)]/4
x = (3/4)[1+isqrt(5)] or x = (3/4)[1 - isqrt(5)]
==========
Cheers,
Stan H.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.
Get all terms to the left side.
Notice we have a quadratic equation in the form of where , , and
Let's use the quadratic formula to solve for x
Start with the quadratic formula
Plug in , , and
Negate to get .
Square to get .
Multiply to get
Subtract from to get
Multiply and to get .
Simplify the square root (note: If you need help with simplifying square roots, check out this solver)
or Break up the expression.
So our answers are or
which approximate to or
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