SOLUTION: I need help solving this word problem which I'm supposed to solve using a quadratic equation. Any help would be appreciated. thanks.
A designer attempts to arrange the chara
Algebra.Com
Question 144532: I need help solving this word problem which I'm supposed to solve using a quadratic equation. Any help would be appreciated. thanks.
A designer attempts to arrange the characters of his artwork in the form of a square grid with equal numbers of rows and columns, but finds that 24 characters are left out. When he tries to add one more row and column, he finds that he has 25 too few characters. Find the number of characters used by the designer.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
He has n characters.
If he makes it x by x, he has 24 left over, so n = x^2+24
If he makes it (x+1) by (x+1), he's 25 short, so n = (x+1)^2 - 25
Since both equal n
2x = 48
x = 24
n = 24*24 + 24 = 600
25*25 is 625, so he would be 25 short.
There was no need to solve a quadratic.
RELATED QUESTIONS
I am struggling with this problem I need to solve
it using quadratic formula. Any help (answered by Edwin McCravy)
My problem involves solving quadratic equations using the zero product property.
I... (answered by scott8148)
Okay, I need help!!
2x^5/7y62 X 21y^11/5x^9
I appreciat any... (answered by ankor@dixie-net.com)
A spool contains 25 1/3 yards of ribbon. It takes 2 ½ yards of ribbon to make a bow. How... (answered by stanbon)
Could you please help me with the following problem? I am supposed to solve this... (answered by jim_thompson5910)
Find an application for your chosen field--- which is psychology or really anything-- or (answered by ankor@dixie-net.com)
Okay I think I wrote the problem correctly this time. I need help converting this to a... (answered by longjonsilver)
I would appreciat help with this one. Thank you
(1-x)^2=9
I think that I need to set... (answered by Alan3354)
We are solving quadratic equation. I tried to sole this problem, but I'm having some... (answered by ankor@dixie-net.com)