SOLUTION: I have been trying this equation and just can't seem to get it. I have been asked to solve and reduce to a quadratic form. My first answer was 8 sq root u +12=0. But I do not thin

Question 143674: I have been trying this equation and just can't seem to get it. I have been asked to solve and reduce to a quadratic form. My first answer was 8 sq root u +12=0. But I do not think that is correct. I am to use "u" as a substitute for some variable in the equation. I have chosen U to substitute for (t+4). If anyone can let me know if I am in the right direction or how to solve this,much appreciated.
(t+4)^2/3 + 7(t+4)^1/3 +12=0.
This is what i did. 3rd root (u^2) + 7 * 3rd root u +12 =0
3rd root (u squared) + 7 * 3rd root U + 12=0
(1+7) 3rd root U + 12 =0
8 3rd root u = -12, 3rd root u = -12/8 reduced to -3/2
Final answer -3/2+ 3rd root u or -3/2-3rd root u
I have no idea what I am doing here, so any help is appreciated. Thanks.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
You have the correct general idea, but a slightly different substitution makes this much easier to handle.

Let

Substituting:

Factoring:

So:

or

Substituting back:

or:

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