SOLUTION: How do I solve? Find the value of the discriminant to determine the number of real-number solutions for this quadratic equation: 2m^2-m-6=0

SOLUTION: How do I solve? Find the value of the discriminant to determine the number of real-number solutions for this quadratic equation: 2m^2-m-6=0

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Question 143569This question is from textbook prentice hall algebra 1
: How do I solve? Find the value of the discriminant to determine the number of real-number solutions for this quadratic equation:
2m^2-m-6=0 This question is from textbook prentice hall algebra 1

Answer by nabla(475) (Show Source): You can put this solution on YOUR website!
The discriminant is
for ax^2+bx+c=0.
So, for our purposes here, the discriminant is:
1-4(2)(-6)=1+48=49. Since it is positive, there will be two real solutions.
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