SOLUTION: Solve using the quadratic formula:
y^2-3y-10=0
Algebra.Com
Question 143158: Solve using the quadratic formula:
y^2-3y-10=0
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
y^2-3y-10=0
y=(3+-sqrt[-3^2-4*1*-10])/2*1
y=(3+-sqrt[9+40])/2
y=(3+-sqrt49)/2
y=3+-7)/2
y=(3+7)/2
y=10/2
y=5 answer.
y=(3-7)/2
y=-4/2
y=-2 answer.
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